Answer:- Bromide concentration is 80748 ppm.
Solution:- ppm is milligram per liter. Grams of magnesium bromide are given and we are asked to calculate the ppm concentration of bromide ion, So, let's first calculate the grams of bromide and then divide it by the given volume.
Molar mass of Magnesium bromide = [tex]24.305+2(126.90)=278.105[/tex]
[tex]115.91gMgBr_2(\frac{1molMgBr_2}{278.105gMgBr_2})(\frac{2molBr}{1molMgBr_2})(\frac{126.90gBr}{1molBr})[/tex]
= 105.78 g Br
Let's convert grams of Br to milligrams:
since, 1 g = 1000 mg
[tex]105.78g(\frac{1000mg}{1g})[/tex]
= 105780 mg
concentration of Br = [tex]\frac{105780mg}{1.31L}[/tex]
= 80748 mg per liter
Since, 1 ppm = 1 mg per liter
So, the bromide concentration is 80748 ppm.
