Monica is mixing some custom colored paint for her house. The color she wants requires 3/4 ounces of blue dye and 2/3 of an ounce of pink dye mixed with each gallon of white paint base. How much dye is needed to mix 8 gallons of paint?

A. 11 5/7
B. 11 2/3
C. 11 1/3
D. 11 2/3

Respuesta :

Amount of blue dye mixed with one gallon of white paint=[tex]\frac{3}{4}[/tex]

Amount needed for 8 gallons = [tex]\frac{3}{4}\times8=6[/tex] ounce

Amount of pink dye mixed with one gallon of white paint=[tex]\frac{2}{3}[/tex]

Amount needed for 8 gallons = [tex]\frac{2}{3}\times8= \frac{16}{3}[/tex] ounces

So, total dye required =[tex]6+\frac{16}{3}=\frac{18+16}{3}=\frac{34}{3}[/tex]

or

[tex]11\frac{1}{3}[/tex] ounces.

Hence, option C is correct.

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