Answer:
The device consumes a power of 55 watts.
Step-by-step explanation:
According to the Joule's Law, [tex]P=I^2R[/tex] , where [tex]P=[/tex] Power in watts, [tex]I=[/tex] Current in amperes and [tex]R=[/tex] Resistance in ohms.
Given that, the device has resistance of 220 ohms and it draws a current of 0.5 ampere. That means, [tex]R=220[/tex] ohms and [tex]I=0.5[/tex] ampere.
Plugging these values into the above formula, we will get.........
[tex]P=(0.5)^2*220\\ \\ P=0.25*220=55[/tex]
So, the device consumes a power of 55 watts.
