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Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 11 people took the trip. She was able to purchase coach tickets for $210 and first class tickets for $1200. She used her total budget for airfare for the trip, which was $10,230. How many first class tickets did she buy? How many coach tickets did she buy?

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You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.

$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)

x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)

Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:

$210x + $1200(11 - x) = $10,230

$210x + $13,200 - $1200x = $10,230

-$990x + $13,200 = $10,230

-$990x = $2,970

x = 3


Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:

3 + y = 11

y = 8


Sarah bought y = 8 first class tickets.

The number of coach tickets purchased is 3, and the number of first-class tickets purchased is 8.

Let us assume the number of coach tickets purchased is x.

And the number of first-class tickets purchased is y.

Now,

Including Sarah, a total of 11 people took the trip.

Thus,

[tex]x+y=11[/tex]      ............(1)

The cost of coach tickets and first-class tickets are $210 and $1200 respectively.

The total budget for airfare for the trip is $10,230.

Therefore,

[tex]210x+1200y=10230\\21x+120y=1023[/tex]............(2)

Solving both the equations, we get.

[tex]x=3\\y=8[/tex]

Thus, The number of coach tickets purchased is 3, and the number of first-class tickets purchased is 8.

To know more about it, please refer to the link:

https://brainly.com/question/7480814