Evaluating a piece wise defined function
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Given : If x ≠ -2 then f(x) = [tex]\frac{3}{4}x - 1[/tex]
As -5 ≠ -2 ⇒ f(-5) = [tex]\frac{3}{4}(-5) - 1 = (\frac{-15}{4} - 1) = \frac{-19}{4}[/tex]
Given : if x = -2 then f(x) = -1
As x = -2 ⇒ f(-2) = -1
Given : If x ≠ -2 then f(x) = [tex]\frac{3}{4}x - 1[/tex]
As 2 ≠ -2 ⇒ f(2) = [tex]\frac{3}{4}(2) - 1 = (\frac{3}{2} - 1) = \frac{1}{2}[/tex]