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carlosego

The answer is: [tex]6.25\leq6.3<6.35[/tex]

The explanation is shown below:

1. Cynthia rounds the number, which is identified as [tex]x[/tex], to one decimal place and the result is 6.3.

2. Based on this, we know that [tex]x[/tex] could have been between 6.25 and 6.35. Therefore, the error interval for [tex]x[/tex] is given by:

 [tex]6.25\leq6.3<6.35[/tex]

Where [tex]\leq[/tex] indicates that the value 6.25 is included and [tex]<[/tex] indicates that the value 6.35 is not included (Because if [tex]x[/tex] had been exactly 6.35, Cynthia would round up to 6.4).

MrRoyal

The error interval of x is [tex]6.24\le x \le 6.35[/tex]

The approximated number is given as: 6.3

The number is given as x.

So, we have:

x = 6.3

The smallest number that can be approximated to 6.3 is 6.25 (to 1 decimal place), while the largest number is 6.34

Given that there are possibilities of error, the lower and upper bound of the error interval would be:

[tex]6.25 - 0.01\le x \le 6.34 + 0.01[/tex]

[tex]6.24\le x \le 6.35[/tex]

Hence, the error interval of x is [tex]6.24\le x \le 6.35[/tex]

Read more about approximation at:

https://brainly.com/question/10171109

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