Type the correct answer in the box. Express the answer to three significant figures.

Given:
CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ/mol

How much energy is released when 59.7 grams of methane (CH4) reacts with oxygen?

The combustion of 59.7 grams of methane releases
34.5
kilojoules of energy.

Respuesta :

Answer : The energy released is -3319.7 KJ.

Solution : Given,

Mass of methane = 59.7 g

Molar mass of methane = 16 g/mole

[tex]\Delta H=-890KJ/mole[/tex]

The value of [tex]\Delta H[/tex] is in negative that means the energy is releasing.

First we have to calculate the moles of methane.

Moles of methane = [tex]\frac{\text{ Mass of methane}}{\text{ Molar mass of methane}}= \frac{59.7g}{16g/mole}=3.73moles[/tex]

Now we have to calculate the amount of energy released.

The given reaction is,

[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]

From the reaction, we conclude that

1 mole of methane releases -890 KJ/mole of energy

3.73 moles of methane releases [tex]\frac{-890KJ/mole}{1mole}\times 3.73mole=-3319.7KJ[/tex] of energy

Therefore, the energy released is -3319.7 KJ.

Answer:

3310

Explanation:

I got it correct in my test :)

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