What volume of water vapor will be produced from the reaction of 24.65 L of oxygen?

You don’t give the reaction. However, if all the H₂O comes from O₂, we can write a partial equation. The important point is that we must balance the O atoms.

O₂ + … ⟶ 2H₂O + …

V/L: 1 L 2 L

2. Calculate the volume of N₂.

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

According to the law, 1 L of O₂ produces 2 L of H₂O.

Then, the conversion factor is (2L H₂O/1 L O₂).

Volume of H₂O = 24.65 × 2/1

Volume of H₂O = 49.30 L

BarrettArcher BarrettArcher · Answer 2 · 2019-01-21T09:23:17+01:00

Answer : The volume of water vapor produced will be, 49.3 L

Solution : Given,

Volume of oxygen = 24.65 L

As we know that,

At STP, 1 mole of gas occupies 22.4 liter of volume

The balanced chemical reaction will be,

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]

From the balanced reaction, we conclude that

2 moles of hydrogen react with the 1 mole of oxygen to give 2 moles of water vapor.

1 mole of oxygen contains 22.4 L of volume and 2 moles of water vapor contains [tex]2\times 22.4L[/tex] of volume

As, 22.4 L of oxygen produces volume of water vapor = [tex]2\times 22.4L[/tex]

So, 24.65 L of oxygen produces volume of water vapor = [tex]\frac{2\times 22.4L}{22.4L}\times 24.65L=49.3L[/tex]

Therefore, the volume of water vapor produced will be, 49.3 L