Given:
Initial velocity(u): 25 m/s
Final velocity(v): 0 m/s
Time : 0.42 secs
Now we know that
v=u+at
Where v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
Substituting the given values we get
v=u+at
0=25+a x 0.42
a= -59.52 m/s^2
Now we also know that
v^2= u^2 + 2as
Where v is the final velocity measured in m/s
u is the initial velocity measured in m/s
a is the acceleration measured in m/s^2
s is the displacement/distance traveled measured in m.
Now substituting the given values in the above formula we get
v^2= u^2 + 2 as
0= 25^2 - (2 x 59.52 x s)
s = 5.25 m
Thus the distance traveled is 5.25 m.
