The number of Ml of 0.80 M sucrose solution that contain
(A) 7.45 g are 27.25 Ml
calculation
volume= moles /molarity
molarity = 0.80 M which is the same as 0.80 mol/l
moles= mass/molar mass
= 7.45 g/ 342.3 g/mol =0.0218 moles
volume is therefore = 0.0218 moles / 0.80 mol/L=0.02725 L
convert into ml by multiplying by 1000
= 27.25 ml
volume = moles/molarity
molarity = 0.80 M = 0.80 Mol/L
moles =mass/molar mass
mass 17.0 mg convert into g by diving by 1000=0.017 g
moles is therefore = 0.017 g/ 342.3 g/mol = 4.97 x10^-5 moles
volume = (4.97 x 10^-5 moles) /0.8 mol /l=6.21 x10^-5 L
= 6.21 x10^-5 x 1000 =0.0621 Ml
