find the point of the intersection for the given systems y=x^2+1 and y=x+1
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set them equal to each other
x²+1=x+1
minus 1 from both sides
x²=x
minus x both sides
x²-x=0
factor
x(x-1)=0
set each to 0
x=0
x-1=0
x=1
subsitute back to find y values
y=x+1, y=0+1, y=1, one point is (0,1)
y=x+1, y=1+1, y=2, another point is (1,2)
the 2 points of intersection are (0,1) and (1,2)