Respuesta :
Alright, lets get started.
Please refer the attached diagram.
400N is applied with angle 65 degrees.
So, there will be two components of the force.
X component will be = fx1 = 400 cos 65
X component will be fx1 = [tex]400*0.422618 = 169.05[/tex] N
Y component will be fy1 = 400 sin 65
Y component will be fy1 = [tex]400*0.90630 = 362.5[/tex]
Similarly, 600 N force is applied on angle 110degrees, so the components will be
X component fx2 = -600 cos 80
X component fx2 = -[tex]600*0.1736481 = -104.19[/tex]
Y component fy2 = 600 sin 80
Y component fy2 = [tex]600 * 0.98480 = 590.88[/tex]
So, combined X component will be = [tex]169.05-104.19 = 64.86[/tex]
Combined Y component will be = [tex]362.5 + 590.88 = 953.38[/tex]
So, magnitude will be = [tex]\sqrt{64.86^2 + 953.38^2} = 955.58 N[/tex]
So the magnitud of combined force will be 955.58 N. : Answer
Hope it will help :)
