Respuesta :
We are actually given a theorem that states that the sum of the interior angles of a regular n-gon is
[tex] (n-2)\times \pi [/tex]
Since all the interior angles of a regular n-gon have the same measure, each of these angles measures
[tex] \dfrac{(n-2)\times \pi}{n} [/tex]
radians. So, you don't need any inequality, because we know the exact value of any of the angles.
When you are presented with a theory that claims that the sum of the interior angles of a regular n-gon is equal to
[tex]\to (n-2) \times \pi[/tex]
- When all of the interior angles of a standard n-gon have the same measure, each of these angles has the same indicator.
[tex]\to \frac{(n-2) \times \pi}{n}[/tex]
- Radians, Therefore, no inequality is needed because we know the exact value of each angle.
OR
The interior angle of n-gon is:
[tex]\to x=180^{\circ}-\frac{360^{\circ}}{n}\\\\\to x \geq 180^{\circ} - \frac{360^{\circ}}{n}\\\\[/tex]
Therefore, the "n" is the side of n-gon.
Learn more about the interior angles of a regular n-gon:
brainly.com/question/3143390
