Given that :
Mass of [tex]CO_{2}[/tex] = 6.59 g
Mass of [tex]H_{2}O[/tex] = 2.7 g
Total mass of compound = 2.9 g
Explanation :
From given data,
Mass of C in 6.59 g [tex]CO_{2}[/tex] = [tex]\frac{12}{44*6.59} = \frac{12}{289.96} = 0.0414 g[/tex]
Mass of H in 2.7 g [tex]H_{2}O[/tex] = [tex]\frac{2}{18*2.7} = \frac{2}{48.6} = 0.0412 g[/tex]
Mass of O = 2.9-(0.0414+0.0412) = 2.82 g
Moles of each atoms
C = [tex]\frac{0.0414}{12} = 0.00345[/tex]
H = [tex]\frac{0.0412}{1} = 0.0412[/tex]
O = [tex]\frac{2.82}{16} = 0.176[/tex]
Simpler ratio of moles for each atom
C = [tex]\frac{0.00345}{0.00345} =1[/tex]
H = [tex]\frac{0.0412}{0.00345} = 12[/tex]
O = [tex]\frac{0.176}{0.00345} = 51[/tex]
According to above given values the possible formula for compound will be
[tex]CH_{12} O_{51}[/tex]
