Respuesta :

malika8888
2H2(g) + O2(g)=2H2O -483.64 kJ
2 mol. of H2O ----> -483.64 kJ
1 mol. of H2O ----> X

[tex]x = \frac{1 \times - 483.64}{2} = -241,82 \: kj[/tex]

Answer : The amount of energy released is, -241.82 KJ

Explanation : Given,

[tex]\Delta H_{rxn}=-483.64KJ[/tex]

The balanced chemical reaction is,

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]

From this we conclude that,

As, 2 moles of [tex]H_2O[/tex] released amount of energy = -483.64 KJ

So, 1 mole of [tex]H_2O[/tex] released amount of energy = [tex]\frac{-483.64KJ}{2}=-241.82KJ[/tex]

Therefore, the amount of energy released is, -241.82 KJ

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