Respuesta :
P=x
V=6.23 L
n= 0.25 mol
R=0.082
T= 35°C
K=273+C°
K=273+35=308 K
PV=nRT
[tex]PV=nRT \: \\ x \times 6.23 = 0.25 \times 0.082 \times 308 \\ x = 1 \: atm[/tex]
1 atm = 101.325 kPa
1 atm = x
x= 101.325 kPa
The absolute pressure of the air in the balloon is 101.325 kilopascals.
V=6.23 L
n= 0.25 mol
R=0.082
T= 35°C
K=273+C°
K=273+35=308 K
PV=nRT
[tex]PV=nRT \: \\ x \times 6.23 = 0.25 \times 0.082 \times 308 \\ x = 1 \: atm[/tex]
1 atm = 101.325 kPa
1 atm = x
x= 101.325 kPa
The absolute pressure of the air in the balloon is 101.325 kilopascals.