Answer:
0.165 mol·L⁻¹
Explanation:
1. Write the chemical equation for the reaction.
HNO₃ + KOH ⟶ KNO₃ + H₂O
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2. Calculate the moles of HNO₃
c = n/V Multiply each side by V and transpose
n = Vc
V = 0.027 86 L
c = 0.1744 mol·L⁻¹ Calculate the moles of HNO₃
Moles of HNO₃ = 0.027 86 × 0.1744
Moles of HNO₃ = 4.859 × 10⁻³ mol HNO₃
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3. Calculate the moles of KOH
1 mol KOH ≡ 1 mol HNO₃ Calculate the moles of KOH
Moles of KOH = 4.859 × 10⁻³× 1/1
Moles of KOH = 4.859 × 10⁻³ mol KOH
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4. Calculate the molar concentration of the KOH
V = 29.4 mL = 0.0294 L Calculate the concentration
c = 4.859 × 10⁻³/0.0294
c = 0.165 mol·L⁻¹
