The volume (in liters) of CO₂ that can be consumed at STP by 435 g Na₂O₂ is 125 L of Co₂
calculation
2Na₂O₂(s) +2 CO₂ (g)→ 2 Na₂CO₃(s) + O₂(g)
Step 1 : find the moles of Na₂O₂
moles = mass÷ molar mass
from periodic table the molar mass of Na₂O₂ = (23 x2) +( 16 x2) = 78 g/mol
moles= 435 g÷ 78 g/mol = 5.58 moles
Step 2: use the mole ratio to determine the moles of CO₂
from given equation Na₂O₂ : CO₂ =2 :2 =1:1
Therefore the moles of CO₂ is also = 5.58 moles
Step 3: find the volume of CO₂ at STP
that is at STP 1 mole of a gas = 22.4 L
5.58 moles = ? l
by cross multiplication
= (5.58 moles x 22.4 L) / 1 mole = 125 L
Volume is the scalar amount of the space occupied by the substance in the given area. At STP the volume of carbon dioxide is 125 L.
STP is the standard temperature and pressure condition that are used as the references to compare the other gases.
The balanced chemical reaction can be shown as:
[tex]\rm 2Na_{2}O_{2}(s) +2 CO_{2} (g) \rightarrow 2 Na_{2}CO_{3}(s) + O_{2}(g)[/tex]
The moles of Sodium peroxide can be calculated as:
[tex]\begin{aligned}\rm moles& = \rm \dfrac{mass}{molar \; mass}\\\\&= \dfrac{435}{78}\\\\&= 5.58 \;\rm mol\end{aligned}[/tex]
Now the moles of carbon dioxide can be determined by the mole of the Sodium peroxide as the ratio of both is 1:1 so moles of carbon dioxide will be 5.58.
The volume of carbon dioxide at STP can be calculated as:
1 mole of gas = 22.4 L at STP
So, 5.58 moles of carbon dioixde = ?
[tex]\dfrac{5.58 \times 22.4}{1} = 125 \;\rm L[/tex]
Therefore, at STP the volume of carbon dioxide is 125 L.
Learn more about STP and volume here:
https://brainly.com/question/20911369
