Answer: 1
Step-by-step explanation:
Method #1: Using the log rules (+ → x and - → ÷)
log₂4 + log₂16 - log₂32
= log₂[tex](\frac{4*16}{32})[/tex]
= log₂[tex](\frac{64}{32})[/tex]
= log₂2
= 1
Method #2: Using log rules to simplify each expression
log₂4 = x log₂16 = x log₂32 = x
4 = 2ˣ 16 = 2ˣ 32 = 2ˣ
2² = 2ˣ 2⁴ = 2ˣ 2⁵ = 2ˣ
2 = x 4 = x 5 = x
log₂4 = 2 log₂16 = 4 log₂32 = 5
2 + 4 - 5 = 1
