Respuesta :
35.5 g of chlorine is 1 mole of chlorine.
The answer is Avogadro's Number 6.02 x 10^23 atoms. 1 mole of every element has this number of atoms.
Answer: Option (B) is the correct answer.
Explanation:
According to Avogadro's number, one mole of a substance contains [tex]6.022 \times 10^{23}[/tex] atoms or molecules.
As molar mass of chlorine is 35.5 g/mol. Hence, calculate its number of moles as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{35.5 g}{35.5 g/mol}[/tex]
= 1 mol
Therefore, number of atoms present in 1.01 mol are calculated as follows.
[tex]1 mol \times 6.022 \times 10^{23}[/tex] atoms/mol
= [tex]6.02 \times 10^{23}[/tex] atoms
Therefore, we can conclude that there are [tex]6.02 \times 10^{23}[/tex] atoms in 35.5 g of chlorine.
