Answer:
0.52 m
Explanation:
The motion of the studnet is an accelerated motion, with constant acceleration [tex]g=9.8 m/s^2[/tex] (acceleration of gravity) toward the ground. We can find the distance covered by the student (which is equal to the height from which he falls) by using the SUVAT equation:
[tex]v^2 -u^2 = 2ad[/tex]
where
v = 3.2 m/s is the final speed
u = 0 is the initial speed
a = 9.8 m/s^2 is the acceleration
d is the distance covered
By re-arranging the equation, we find:
[tex]d=\frac{v^2-u^2}{2a}=\frac{(3.2 m/s)^2-0}{2(9.8 m/s^2)}=0.52 m[/tex]
