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The following equation is one way to prepare oxygen in a lab. 2KClO3 → 2KCl + 3O2 Molar mass Info: MM O2 = 32 g/mol MM KCl = 74.55 g/mol MM KClO3 = 122.55 g/mol If 25.6 g of KCl are produced, then how many moles of KClO3 were consumed?

0.209 mol
0.687 mol
0.343 mol
0.172 mol

Respuesta :

kenmyna

The moles of KClO₃  that were consumed  is  0.343  moles

    calculation

2KClO₃ →  2KCl +3O₂

 step  1: find the  moles    KCl

moles   = mass÷ molar mass

 25.6 g÷74.55 g/mol =0.343  moles

Step 2 : use the  mole  ratio to determine    the  moles  KClO₃

  from  equation above KClO₃ : KCl  is 2:2  =1:1

     therefore   the  moles  KClO₃  = 0.343  moles


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