Answer:
[tex]65^\circ[/tex]
Step-by-step explanation:
It is given that the measure of angle JKL can be represented by [tex](3x+5)[/tex].
And from the figure we can see that the measure of angle JKL is,
[tex](45^\circ+x^\circ)[/tex]
Both the measures must be equal, hence equating both the angles we get,
[tex](3x+5)=45+x[/tex]
Solving for 'x' we get,
[tex]3x+5=45+x[/tex]
[tex]3x-x=45-5[/tex]
[tex]2x=40[/tex]
[tex]x=\frac{40}{2}[/tex]
[tex]x=20[/tex]
Putting the value of 'x' we can calculate the measure of angle JKL,
[tex]45^\circ+x^\circ=45^\circ+20^\circ=65^\circ[/tex]
Therefore, the measure of angle JKL is, [tex]65^\circ[/tex].
