Maricella’s strategy is incorrect as the values added on the left and right side of the equation changes the original equation [tex]4x-2(3x-4)+4=-x+3(x+1)+1[/tex] to [tex]4x-2(3x-4)+4=-x+3(x+1)+3[/tex].
Further explanation:
Maricella begin by adding [tex]-4+4[/tex] on the left side of the equation and [tex]1+1[/tex] on the right side of the equation [tex]4x-2(3x-4)+4=-x+3(x+1)+1[/tex].
The value added on the left is equal to zero so it does not change the equation but the value added on the right is 2, a non-zero digit so it changes the equation as shown below.
[tex]4x-2(3x-4)+4-4+4=-x+3(x+1)+1+1+1\\4x-2(3x-4)+4+0=-x+3(x+1)+1+2\\4x-2(3x-4)+4=-x+3(x+1)+3[/tex]
Therefore, the strategy used by Maricella will change the equation and so the solution of the equation will be incorrect.
One way of solving such a linear equation is by adding or subtracting the required value on each side of the equation. and then simplifying the further equation.
Similarly, the other way to solve any linear equation is by separating the variable terms on one side of the equation and constant terms on the other side of the equation.
After this simplify the linear equation to obtain the solution of the equation for [tex]x[/tex].
Whereas Maricella’s strategy fails to solve the equation [tex]4x-2(3x-4)+4=-x+3(x+1)+1[/tex] since the values added and subtracted in the equation changes the original equation completely.
Learn more:
1. Linear equation application https://brainly.com/question/2479097
2. To solve one variable linear equation https://brainly.com/question/1682776
3. Binomial and trinomial expression https://brainly.com/question/1394854
Answer details
Grade: Middle school
Subject: Mathematics
Chapter: Linear equation
Keywords: equation, linear equation, Maricella, right side, left side, strategy, solve for [tex]x[/tex], adding, subtracting, variable, constant, solution of the equation, value, original equation, variable terms, constant terms.
