HELP!!!!
Which expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9)?
A) 1-(-7)/ -9-3
B) 1+(-7)/-9+3
C) -9-3/1-(-7)
D) -9+3/1+(-7)

Respuesta :

Initial point = (a,b) = (-7,3)
Final point = (x-y) = (1,-9)

[tex]Slope \: m = \frac{y - b}{x - a} \\ putting \: values, \\ m = \frac{ - 9 - 3}{1 - ( - 7)} [/tex]

So,
The Answer will be option C). -9-3/1-(-7)

!! Hope It Helps !!

The expression can be used to determine the slope of the line that passes through the points (–7, 3) and (1, –9) is -9-3/1-(-7).

What is a straight line graph?

  • The graph follows a straight line equation shows a straight line graph.
  • equation of a straight line is   y=mx+cy represents vertical line y-axis.
  • x represents the horizontal line x-axis.    
  • m is the slope of the line

            slope(m)=tan∅=y axis/x axis.

  • c represents y-intercepts (it is the point at which the line cuts on the y-axis)

Straight line graphs show a linear relationship between the x and y values.

solving the equation:-

 Initial point (-7,3)

  Final point  (1,-9)

Slope= [tex]\frac{Y2-y1}{x2-x1}[/tex]

∴Answer will be option C). -9-3/1-(-7)

Learn more about the straight lines here:-https://brainly.com/question/16099437

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