Find the missing numerators in each of the following fractions: a. 5⁄6 = ?⁄12 b. 2⁄4 = ?⁄36 c. 2⁄5 = ?⁄20 d. 4⁄25 = ?⁄100

Respuesta :

akephd
A. 10
Multiply numerator and denominator by 2. So 6(2)=12 and 5(2)=10
B. 18
Multiply numerator and denominator by 9. So 4(9)=36 and 2(9)=18
C. 8
Multiply numerator and denominator by 4. So 5(4)=20 and 2(4)=8
D. 16
Multiply numerator and denominator by 4. So 25(4)=100 and 4(4)=16

Answer:

To find: Missing Numerators.

let the missing variable in each part be x.

A).

[tex]\frac{5}{6}=\frac{x}{12}[/tex]

[tex]\frac{5}{6}\times12=x[/tex]

[tex]x=10[/tex]

Thus, Missing Numerator in this part is 10.

B).

[tex]\frac{2}{4}=\frac{x}{36}[/tex]

[tex]\frac{2}{4}\times36=x[/tex]

[tex]x=18[/tex]

Thus, Missing Numerator in this part is 18.

C).

[tex]\frac{2}{5}=\frac{x}{20}[/tex]

[tex]\frac{2}{5}\times20=x[/tex]

[tex]x=8[/tex]

Thus, Missing Numerator in this part is 8.

D).

[tex]\frac{4}{25}=\frac{x}{100}[/tex]

[tex]\frac{4}{25}\times100=x[/tex]

[tex]x=16[/tex]

Thus, Missing Numerator in this part is 16.