Answer:
Equation in point-slope form= [tex]{y+3}=\frac{-1}{2}(x+3)[/tex]
Step-by-step explanation:
The given end points are B(−1,1) and C(−5,−7)
Mid point M of BC= [tex]\frac{-5-1}{2}[/tex] , [tex]\frac{-7+1}{2}[/tex]
Mid point M of BC = -3 , -3
Slope of BC = [tex]\frac{-7-1}{-5+1}[/tex] = 2
Slope of bisector= m= [tex]\frac{-1}{2}[/tex]
Equation of perpendicular bisector : [tex]\frac{y+3}{x+3}=\frac{-1}{2}[/tex]
⇒ [tex]{y+3}=\frac{-1}{2}(x+3)[/tex]
⇒ 2(y+3)= -(x+3)
⇒ [tex]2y+x=-9[/tex]
