a volleyball player hit the ball with a mass of 0.25 kg. The average acceleration of the ball is 15.5 m/s2. How much force did the volleyball player apply to the ball?

Respuesta :

Force = Mass × Acceleration

If we're calculating force we know that:

m = 0.25 kg

a = 15.5 m/s^2

And so the force is:

F = m × a = 0.25 kg × 15.5 m/s^2 = 3.875 Newtons

Answer:

3.875 N

The force applied by the volleyball player to the ball is 3.875 N.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Given data:

m = 0.25 kg

a = 15.5 m/s²

Force is defined as the product of mass and acceleration. Its unit is Newton.

Force = Mass × Acceleration

F = m × a

F = 0.25 kg × 15.5 m/s²

F= 3.875 Newtons

Hence, the force applied by the volleyball player to the ball is 3.875 N.

To learn more about the force refer to the link;

https://brainly.com/question/26115859

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