The partial pressure of argon in the jar is 0.0093 atm
calculation
This is calculated using the ideal gas equation
that is PV =nRT
where;
P(pressure) =?
V ( volume)= 25.0 L
n(number of moles) =0.0104 moles
R( gas constant) = -0.0821 L. atm/ mol.K
T( temperature) = 273 K
make p the subject of the formula by diving both side of equation by v
P = nRT/V
P =[(0.0104 mol x 0.0821 L.atm/mol.k x 273 k)/ 25 L ] = 0.0093 atm
