Find the rational zeros and then the other zeros of the polynomial fraction f(x)=x^3+2x^2-3x-6 that is,solve f(x)=0

Hello from MrBillDoesMath!
Answer:
x = -2 and x = +\- sqrt(3)
Discussion:
x^3 + 2x^2 -3x -6 = (x + 2) (x^2 - 3)
so the roots are x = -2 and x = +\- sqrt(3)
Regards,
MrB