Respuesta :
Answer:
Total cost for tiles and paints is $924.
Step-by-step explanation:
We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.
The paint will be required for 4 walls and ceiling.
Let us find area of walls and ceiling.
[tex]\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)[/tex]
[tex]\text{Area of walls and ceiling}=1200+90+120[/tex]
[tex]\text{Area of walls and ceiling}=1410[/tex]
Therefore, the area of walls and ceiling is 1410 square meters.
Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,
[tex]\text{ The total painting cost}=10*(\frac{1410}{25})[/tex]
[tex]\text{ The total painting cost}=10*56.4=564[/tex]
Therefore, the total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor.
[tex]\text{Area of floor} = 40*3\text{ square meters}[/tex]
[tex]\text{Area of floor} =120\text{ square meters}[/tex]
Given: 1m squared floor tiles costs $3. So,
[tex]\text{Total cost for tiles} = 3*120 = 360[/tex]
Therefore, the total cost for tiles is $360.
Now let us find combined total cost of tiles and paint.
[tex]\text{Combined total cost}= 564+360 = 924[/tex]
Therefore, the combined total cost of tiles and paint is $924.
The combined total cost of tiles and paints is $924.
Given data:
The length of community hall is, L = 40 m.
The height of hall is, h = 15 m .
The width of hall is, w = 3 m.
Volume of paint is, V = 10 litre.
The paint will be required for 4 walls and ceiling. Let us find area of walls and ceiling as,
Area of walls and ceiling is,
[tex]=(2 \times 40 \times 15) + (2 \times3 \times 15 )+(40 \times 3)\\= 1200 +90 +120\\=1410 \;\rm m^{2}[/tex]
Since, cost for 10 litre of paint is is $10 and 10 litre paint covers 25 square meter. Therefore,
Total cost of painting is,
[tex]=10 \times \dfrac{1410}{25}\\=564[/tex]
So, total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor as,
Area of floor is,
[tex]=40 \times 3\\=120 \;\rm m^{2}[/tex]
Cost of painting the floor is, $3 per square meter. So, required cost is,
[tex]= 3 \times 120\\=360[/tex]
So, cost for tiles is $360.
Then, Total cost is,
[tex]=564+360\\=924[/tex]
Thus, we can conclude that the combined total cost of tiles and paint is $924.
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