The population of a town increased by 15% in 2016, and decreased by 5% in 2017. If the population of the town was 60,000 in the beginning of 2016, then what was it at the end of 2017?

Respuesta :

Answer:

65,550.

Step-by-step explanation:  

We have been given that the population of a town increased by 15% in 2016, and decreased by 5% in 2017.

Since an exponential is in form: [tex]a*b^x[/tex].  

For growth b=(1+r), where r in rate in decimal form.  

For decrease b=(1-r), where r in rate in decimal form.

[tex]15\text{ percent}=\frac{15}{100}=0.15[/tex]

Let us find the population increase in 2015.

[tex]\text{Population at the end of year 2016}= 60,000*(1+0.15)^1[/tex]  

[tex]\text{Population at the end of year 2016}= 60,000*(1.15)[/tex]  

[tex]\text{Population at the end of year 2016}= 69,000[/tex]

Therefore, the population at the end of year 2016 will be 69,000.

Now let us find population decrease of 5% in year 2017.

[tex]15\text{ percent}=\frac{5}{100}=0.05[/tex]

[tex]\text{Population at the end of year 2017}= 60,000*(1-0.05)^1[/tex]  

[tex]\text{Population at the end of year 2017}= 60,000*(0.95)[/tex]  

[tex]\text{Population at the end of year 2017}= 65,550[/tex]  

Therefore, the population at the end of year 2017 will be 65,550.