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Two times the sum of three consecutive odd integers is fifteen more than three times the largest of the integers. Find the integers?

Respuesta :

tramserran

Answer: 5, 7, 9

Step-by-step explanation:

1st#: 2k+1

2nd#: 2k+3

3rd#: 2k+5


2(2k+1 + 2k+3 + 2k+5) = 3(2k+5) + 15

2(6k + 9) = 6k + 15 + 15

12k + 18 = 6k + 30

6k           =        12

 k           =         2


1st#: 2k+1  = 2(2) + 1 = 5

2nd#: 2k+3 = 2(2) + 3 = 7

3rd#: 2k+5 = 2(2) + 5 = 9

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