Answer:
The 3rd equation on the left column and second one on the right column.
Step-by-step explanation:
These 2 equations have same coefficients of x and y if we divide the first one by 4 and the second by 2.
This gives the 2 equations
x^2 + y^2 - 4x + 6y - 7 = 0
x^2 + y^2 - 4x + 6y - 20 = 0
If we compete the square on these we get
(x - 2)^2 + (y + 3)^2 = 20
(x - 2(^2 + (y + 3)^2 = 33
These are in standard form . The center is the same (2, -3) but the radii are different so they are concentric.
