Answer:
option C
[tex]f(x)=-\sqrt{x+3}+8[/tex]
Step-by-step explanation:
we have
[tex]f(x)=-2\sqrt{x-3}+8[/tex]
using a graphing tool
see the attached figure N[tex]1[/tex]
The range is the interval--------> (-∞,8]
[tex]y\leq 8[/tex]
case A) [tex]f(x)=\sqrt{x-3}-8[/tex]
using a graphing tool
The range is the interval--------> [-8,∞)
[tex]y\geq -8[/tex]
case B) [tex]f(x)=\sqrt{x-3}+8[/tex]
using a graphing tool
The range is the interval--------> [8,∞)
[tex]y\geq 8[/tex]
case C) [tex]f(x)=-\sqrt{x+3}+8[/tex]
using a graphing tool
The range is the interval--------> (-∞,8]
[tex]y\leq 8[/tex]
case D) [tex]f(x)=-\sqrt{x-3}-8[/tex]
using a graphing tool
The range is the interval--------> (-∞,-8]
[tex]y\leq -8[/tex]
