Respuesta :
The liters in 3.25 g of ammonia 4.28 L
calculation
Step 1: find moles of ammonia
moles = mass÷ molar mass
From periodic table the molar mass of ammonia (NH₃) = 14 +(1×3 ) = 17 g/mol
3.25 g÷ 17 g/mol = 0.191 moles
Step 2: find the number of liters of ammonia
that is at STP 1 moles = 22.4 L
0.191 moles = ? L
by cross multiplication
={( 0.191 moles ×22.4 L) / 1 mole} = 4.28 L
Answer:
The volume of 3.25 grams of ammonia is 4.28 L
Explanation:
Step 1: Data given
Mass of ammonia = 3.25 grams
Molar mass of ammonia = 17.03 g/mol
Step 2: Calculate moles ammonia
Moles NH3 = mass NH3 / molar mass NH3
Moles NH3 = 3.25 grams / 17.03 g/mol
Moles NH3 = 0.191 moles
Step 3: Calculate volume of NH3
1 mol = 22.4 L
0.191 moles = 22.4 * 0.191 = 4.28 L
The volume of 3.25 grams of ammonia is 4.28 L