Respuesta :

 The liters in   3.25 g   of  ammonia  4.28 L


  calculation

 Step 1: find moles of ammonia

 moles = mass÷ molar  mass

 From  periodic    table  the molar mass  of ammonia (NH₃)  =  14 +(1×3 ) = 17  g/mol

3.25 g÷ 17 g/mol = 0.191   moles

Step 2: find the number of liters of ammonia

 that is at STP  1  moles = 22.4 L

                        0.191 moles = ? L

by cross  multiplication

 ={( 0.191   moles  ×22.4 L) / 1 mole}  = 4.28 L



Answer:

The volume of 3.25 grams of ammonia is 4.28 L

Explanation:

Step 1: Data given

Mass of ammonia = 3.25 grams

Molar mass of ammonia = 17.03 g/mol

Step 2: Calculate moles ammonia

Moles NH3 = mass NH3 / molar mass NH3

Moles NH3 = 3.25 grams / 17.03 g/mol

Moles NH3 = 0.191 moles

Step 3: Calculate volume of NH3

1 mol = 22.4 L

0.191 moles = 22.4 * 0.191 = 4.28 L

The volume of 3.25 grams of ammonia is 4.28 L