Set the entire expression equal to 0 and solve.
[tex]0=4x^2-12x+9\\0=(2x-3)(2x-3)\\\\[/tex]
So [tex]2x-3 = 0\\2x=3\\x=3/2[/tex]
Or....If you know the quadratic formula use that.
Your answer would be 2 x-intercepts but only one point on the graph where the parabola crosses the x-axis
There are 2 x-intercepts does the graph of y=4x^2-12x+9 which is 3/2.
The x-intercept (s) of a function are the points at which the graph of the function intersect the x-axis.
The given function is;
[tex]\rm y=4x^2-12x+9[/tex]
To find the value of x-intercept substitute y = 0 in the equation;
[tex]\rm y=4x^2-12x+9\\\\y=0\\\\4x^2-12x+9=0\\\\4x^2-6x-6x+9=0\\\\2x(2x-3)-3(2x-3)=0\\\\(2x-3)(2x-3)=0\\\\2x-3=0\\\\2x=3\\\\x=\dfrac{3}{2}[/tex]
Hence, there are 2 x-intercepts does the graph of y=4x^2-12x+9 which is 3/2.
Learn more about intercept here;
https://brainly.com/question/14264271
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