contestada

3) A driver in a 1000-kg car traveling at 24 m/s slams on the brakes and skids to a stop. If the coefticient of friction between the tires and the level road is 0 80 how long will the skid marks be? A) 37 m B) 30 m C) 34 m D 46 m

Respuesta :

Answer:

A) 37 m

Explanation:

When the driver slams on the brakes, the force of friction acting on the car provides the deceleration that will cause the car to stop, according to Newton's second law:

[tex]-\mu mg = ma[/tex]

where

[tex]\mu = 0.80[/tex] is the coefficient of friction

m = 1000 kg is the mass of the car

g = 9.8 m/s^2

a is the deceleration

Substituting into the formula, we find the deceleration:

[tex]a=- \mu g=-(0.80)(9.8 m/s^2)=-7.84 m/s^2[/tex]

Now we can find the length of the skid with the SUVAT equation:

[tex]v^2 - u^2 = 2ad[/tex]

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

d is the length of the skid

Substituting, we find

[tex]d=\frac{v^2 -u^2}{2a}=\frac{0-(24 m/s)^2}{2(-7.84 m/s^2)}=36.7 m \sim 37 m[/tex]