Respuesta :
Answer:
values of j are: 2 , -1
Step-by-step explanation:
We have been given:
[tex]\frac{j+4}{j+2}={2}-\frac{1}{j}[/tex]
We will cross multiply in the above equation we get:
[tex]\frac{j+4}{j+2}=\frac{2j-1}{j}[/tex]
[tex]j^2+4j=2j^2+4j-j-2[/tex]
[tex]2j^2-j^2+4j-4j-j-2[/tex]
[tex]j^2-j-2[/tex]
We will solve the quadratic equation by factorizing:
[tex]j^2-2j+j-2[/tex]
[tex]j(j-2)+1(j-2)[/tex]
[tex](j+1)(j-2)[/tex]
hence, the values of j are: 2 , -1
