Answer:
The correct option is 1.
Step-by-step explanation:
Let the amount invested in utility bound be x. So, the amount invested in saving account is (10000-x).
It is given that the yearly income from the two investments is same.
[tex]\text{9\% of x}=\text{6\% of (10000-x)}[/tex]
[tex]\frac{9}{100}\times x=\frac{6}{100}\times (10000-x)[/tex]
[tex]\frac{9x}{100}=600-\frac{6x}{100}[/tex]
[tex]\frac{9x}{100}+\frac{6x}{100}=600[/tex]
[tex]\frac{15x}{100}=600[/tex]
[tex]15x=60000[/tex]
[tex]x=4000[/tex]
The amount invested in utility bound is $4000.
[tex]10000-x=10000-4000=6000[/tex]
The amount invested in saving account is $6000.