The table below shows the relationship between feet and yards fill in each box to write an algebraic expression to a represent the number of feet and any number of yards

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OrethaWilkison OrethaWilkison · Answer 1 · 2019-01-11T07:04:57+01:00

Answer:

The Direct Variation says that:

[tex]y \propto x[/tex]

Then; the equation becomes: [tex]y =kx[/tex] where k is the constant of variation.

Let y represents the number of feet and f(y) represents the number of yards.

then;

by definition of direct relationship we have;

[tex]f(y) = ky[/tex]

Substitute any values from the given tables to solve for k;

Let y = 3 and f(y) = 1

then;

[tex]1 = 3k[/tex]

Divide both sides by 3 we get;

[tex]k = \frac{1}{3}[/tex]

then, the model of the equation becomes: [tex]f(y) = \frac{1}{3}y[/tex]

In Words : [tex]\frac{1}{3}[/tex] times the number y.

Variable : Let y represents the number of feet.

Model : [tex]f(y) = \frac{1}{3}y[/tex]

An algebraic expression to represents the number of feet in any number of yards, [tex]f(y) = \frac{1}{3}y[/tex]

virtuematane virtuematane · Answer 2 · 2019-01-11T10:46:21+01:00

Answer:

We are asked to write an algebraic equation to represent the number of feet in any number of yards:

Words:

Clearly from the entries in the table we could say that:

The number of feet is three(3) times the number of yards.

Variable:

Let f denotes the number of feet.

and y denotes the number of yards.

Model:

So, finally we could write our algebraic equation in terms of variables as:

[tex]y=\frac{1}{3}f[/tex]