Respuesta :

Answer:

[tex]V=\frac{55}{27}ft^3[/tex]

Step-by-step explanation:

We are given box

whose dimensions are

Length is 3 2/3 feet

so,

[tex]L=3\frac{2}{3} =\frac{3\times 3+2}{3}=\frac{11}{3}[/tex]

Width is 4/18 feet

[tex]W=\frac{4}{18}[/tex]

Height is 2 1/2 feet

so,

[tex]H=2\frac{1}{2} =\frac{2\times 2+1}{2}=\frac{5}{2}[/tex]

now, we can find volume

[tex]V=L\times W\times H[/tex]

now, we can plug values

[tex]V=\frac{11}{3}\times \frac{4}{18}\times \frac{5}{2}[/tex]

now, we can simplify it

and we get

[tex]V=\frac{55}{27}ft^3[/tex]

Answer:

The volume of the planter box=[tex]2\frac{1}{27}[/tex] cubic feet.


Step-by-step explanation:

Given the dimensions of planter cuboid box:

Length of planter box =[tex]3\frac{2}{3}[/tex] feet.

Breath of planter box=[tex]\frac{4}{18}[/tex] feet.

Height of planter box=[tex]2\frac{1}{2}[/tex] feet.


Formula used for volume of cuboid box= (length×breath×height).


Plugging the values in above formula for volume,we get


Volume of box= [tex]3\frac{2}{3}[/tex]× [tex]\frac{4}{18}[/tex]×[tex]2\frac{1}{2}[/tex].

Let us convert mixed fractions in to improper fractions first

Therefore,

[tex]3\frac{2}{3}[/tex] feet= [tex]\frac{11}{3}[/tex]

[tex]2\frac{1}{2}[/tex] feet =[tex]\frac{5}{2}[/tex]

volume =[tex]\frac{11}{3}[/tex]× [tex]\frac{4}{18}[/tex]×[tex]\frac{5}{2}[/tex]

=[tex]\frac{11 \times 5 \times 4}{3 \times 2 \times 18}[/tex]

=[tex]\frac{220}{108}[/tex]

=[tex]2\frac{1}{27}[/tex] cubic feet.


Therefore, the volume of the planter box=[tex]2\frac{1}{27}[/tex] cubic feet.