Respuesta :
Answer:
[tex]V=\frac{55}{27}ft^3[/tex]
Step-by-step explanation:
We are given box
whose dimensions are
Length is 3 2/3 feet
so,
[tex]L=3\frac{2}{3} =\frac{3\times 3+2}{3}=\frac{11}{3}[/tex]
Width is 4/18 feet
[tex]W=\frac{4}{18}[/tex]
Height is 2 1/2 feet
so,
[tex]H=2\frac{1}{2} =\frac{2\times 2+1}{2}=\frac{5}{2}[/tex]
now, we can find volume
[tex]V=L\times W\times H[/tex]
now, we can plug values
[tex]V=\frac{11}{3}\times \frac{4}{18}\times \frac{5}{2}[/tex]
now, we can simplify it
and we get
[tex]V=\frac{55}{27}ft^3[/tex]
Answer:
The volume of the planter box=[tex]2\frac{1}{27}[/tex] cubic feet.
Step-by-step explanation:
Given the dimensions of planter cuboid box:
Length of planter box =[tex]3\frac{2}{3}[/tex] feet.
Breath of planter box=[tex]\frac{4}{18}[/tex] feet.
Height of planter box=[tex]2\frac{1}{2}[/tex] feet.
Formula used for volume of cuboid box= (length×breath×height).
Plugging the values in above formula for volume,we get
Volume of box= [tex]3\frac{2}{3}[/tex]× [tex]\frac{4}{18}[/tex]×[tex]2\frac{1}{2}[/tex].
Let us convert mixed fractions in to improper fractions first
Therefore,
[tex]3\frac{2}{3}[/tex] feet= [tex]\frac{11}{3}[/tex]
[tex]2\frac{1}{2}[/tex] feet =[tex]\frac{5}{2}[/tex]
volume =[tex]\frac{11}{3}[/tex]× [tex]\frac{4}{18}[/tex]×[tex]\frac{5}{2}[/tex]
=[tex]\frac{11 \times 5 \times 4}{3 \times 2 \times 18}[/tex]
=[tex]\frac{220}{108}[/tex]
=[tex]2\frac{1}{27}[/tex] cubic feet.