Two vertical posts stand side by side. The distance between the two poles is 22.25 feet.
Given information:
Two vertical posts stand side by side. One post is 8 feet tall and the other is 17 feet tall. A 24 foot wire is stretched between the tops of the posts.
See the attached figure.
Let x be the distance between the poles.
From the attached figure, the height of the taller pole above the smaller one is 17-8=9 feet.
Now, from the triangle formed by the wire, use the Pythagoras theorem as,
[tex]x^2+9^2=24^2\\x^2=495\\x=22.25[/tex]
Therefore, the distance between the two poles or posts is 22.25 feet.
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https://brainly.com/question/15322533
