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11-01-2019
Mathematics

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13-01-2019

[tex]4\cdot x+4\cdot(-1)=4\cdot(-x)+6\cdot1\\\\4x-4=-4x+6\qquad\text{add 4 to both sides}\\\\4x=-4x+10\qquad\text{add 4x to both sides}\\\\8x=10\qquad\text{divide both sides by 8}\\\\x=\dfrac{10}{8}\\\\\boxed{x=\dfrac{5}{4}=1\dfrac{1}{4}}[/tex]

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