[tex]\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=6.6\\ d=3.6\\ n=32 \end{cases} \\\\\\ a_{32}=6.6+(32-1)3.6\implies a_{32}=6.6+(31)3.6 \\\\\\ a_{32}=6.6+111.6\implies a_{32}=118.2[/tex]
