It is given that parallelogram JKLM is a rectangle and by the definition of a rectangle, ∠JML and ∠KLM are right angles. ∠JML≅∠KLM because . JM⎯⎯⎯⎯⎯≅KL⎯⎯⎯⎯⎯ because , and ML⎯⎯⎯⎯⎯⎯≅ML⎯⎯⎯⎯⎯⎯ by the reflexive property of congruence. By the , △JML≅△KLM . Because , JL⎯⎯⎯⎯≅MK⎯⎯⎯⎯⎯⎯ .

It is given that parallelogram JKLM is a rectangle and by the definition of a rectangle JML and KLM are right angles JMLKLM because JMKL because and MLML by the class=
It is given that parallelogram JKLM is a rectangle and by the definition of a rectangle JML and KLM are right angles JMLKLM because JMKL because and MLML by the class=

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Answer:


Step-by-step explanation:

It is given that the parallelogram JKLM  is a rectangle and by the definition of rectangle, ∠JML and ∠KLM are right angles, ∠JML ≅∠KLM because all right angles are congruent.

\overline{JM}≅\overline{KL} because opposite sides of a parallelogram are congruent, and \overline{ML}≅\overline{ML} by the reflexive property of congruence. By the SAS congruence postulate, ΔJML≅ΔKLM, because corresponding parts of congruent triangles are congruent, \overline{JL}≅\overline{MK}.

Answer:  

  • all right angles are congruent.
  • opposite sides of a parallelogram are congruent
  • SAS congruence postulate
  • corresponding parts of congruent triangles are congruent

Step-by-step explanation:

Given : Parallelogram JKLM  is a rectangle and by the definition of rectangle, [tex]\angle{JML}=\text{ and }\angle{KLM}[/tex] are right angles,

Since all interior angles of rectangle are right angle.

then [tex]\Rightarrow\angle{JML}\cong\angle{KLM}[/tex], because all right angles are congruent.

Also, opposite sides of a parallelogram are congruent.

[tex] \overline{JM}\cong\overline{KL}[/tex]

and [tex]\overline{ML}\cong\overline{ML}[/tex] by the reflexive property of congruence.

Now, by the SAS congruence postulate,

[tex]\triangle{JML}\cong\triangl{KLM}[/tex],

Since corresponding parts of congruent triangles are congruent, ∴

[tex]\overline{JL}\cong\overline{MK}[/tex]

  • The SAS postulate says that if two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle then the two triangles are congruent.