Hello from MrBillDoesMath!
Answer:
(x^2)/9 + y^2 = 1
Discussion:
x = 3cost => x/3 = cost
y = sint
Using (sint)^2 + (cos)^2 =1 and substituting the above x and y values gives:
(x/3)^2 + y^2 = (cost)^2 + (sint)^2 = 1 or
(x^2)/9 + y^2 = 1
Thank you,
MrB
