Answer:
x = - 3 ± 3[tex]\sqrt{2}[/tex]
Step-by-step explanation:
given the equation x² + 6x - 9 = 0
We can solve for x using the quadratic formula
x = ( - b ± [tex]\sqrt{b^2-4ac }[/tex] ) / 2a
with a = 1, b = 6 and c = - 9
x = ( - 6 ± [tex]\sqrt{6^2-(4(1)(-9)}[/tex] ) / 2
= ( - 6 ± [tex]\sqrt{36+36}[/tex] ) / 2
= ( - 6 ± [tex]\sqrt{72}[/tex] ) / 2
= ( - 6 ± 6[tex]\sqrt{2}[/tex] ) / 2
x = - 3 ± 3[tex]\sqrt{2}[/tex]
