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Calculate the magnitude of the force between two 3.60 mC point challenges 9.3 cm apart

Respuesta :

Q = magnitude of charge on each of the two point charge = 3.60 mC = 3.60 x 10⁻³ C

r = distance between the two point charges = 9.3 cm = 0.093 m

k = constant = 9 x 10⁹ Nm²/C²

F = magnitude of the force between the two point charges = ?

according to coulomb's law , force between two charges is given as

F = k Q²/r²

inserting the values

F = (9 x 10⁹) (3.60 x 10⁻³)²/(0.093)²

F = 1.35 x 10⁷ N

The magnitude of the force between two charges which are 9.3 cm apart is 1.35×10⁷ N

Data obtained from the question

  • Charge 1 (q₁) = 3.60 mC = 3.6×10¯³ C
  • Charge 2 (q₂) = 3.60 mC = 3.6×10¯³ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 9.3 cm = 9.3 / 100 = 0.093 m
  • Force (F) =?

How to determine the force

The magnitude of the force between the two charges can be obtained by using the Coulomb's law equation as illustrated below:

F = Kq₁q₂ / r²

F = (9×10⁹ × 3.6×10¯³ × 3.6×10¯³) / (0.093)²

F = 1.35×10⁷ N

Learn more about Coulomb's law:

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