Respuesta :
Q = magnitude of charge on each of the two point charge = 3.60 mC = 3.60 x 10⁻³ C
r = distance between the two point charges = 9.3 cm = 0.093 m
k = constant = 9 x 10⁹ Nm²/C²
F = magnitude of the force between the two point charges = ?
according to coulomb's law , force between two charges is given as
F = k Q²/r²
inserting the values
F = (9 x 10⁹) (3.60 x 10⁻³)²/(0.093)²
F = 1.35 x 10⁷ N
The magnitude of the force between two charges which are 9.3 cm apart is 1.35×10⁷ N
Data obtained from the question
- Charge 1 (q₁) = 3.60 mC = 3.6×10¯³ C
- Charge 2 (q₂) = 3.60 mC = 3.6×10¯³ C
- Electric constant (K) = 9×10⁹ Nm²/C²
- Distance apart (r) = 9.3 cm = 9.3 / 100 = 0.093 m
- Force (F) =?
How to determine the force
The magnitude of the force between the two charges can be obtained by using the Coulomb's law equation as illustrated below:
F = Kq₁q₂ / r²
F = (9×10⁹ × 3.6×10¯³ × 3.6×10¯³) / (0.093)²
F = 1.35×10⁷ N
Learn more about Coulomb's law:
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