Answer:
[tex]y = -\frac{1}{6}x +\frac{31}{3}[/tex]
Step-by-step explanation:
We are to find the equation for the line which is perpendicular to another line with the equation [tex]y = 6x - 5[/tex] and passes through a point (2, 10).
Since the slope of a line which is perpendicular to another line is the negative reciprocal of the other line, therefore the slope of our line will be [tex]-\frac{1}{6}[/tex].
Finding the y-intercept:
[tex]y=mx+c[/tex]
[tex]10=-\frac{1}{6} (2)+c[/tex]
[tex]c=\frac{31}{3}[/tex]
Therefore, the equation of the line will be [tex]y = -\frac{1}{6}x +\frac{31}{3}[/tex].
